- A$204$
- ✓$196$
- C$202$
- D$200$
Frequency of fork $1=200 \,Hz$
Frequency of fork $2=200 \pm 4$
When tape is added frequency of fork $2$ decreases.
When frequency of fork $2$ decreases number of beats increases.
Hence we know frequency of fork $2$ is
$f_2=200-4=196 \,Hz$
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$(A)$ If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is $0.01 \ mm$.
$(B)$ If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is $0.005 \ mm$.
$(C)$ If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is $0.01 \ mm$.
$(D)$ If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is $0.005 \ mm$.
