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$\frac{2}{3} Al_2O_3 \rightarrow \frac{4}{3} Al + O_2,\,$ $\Delta G = +966\,kJ\,mol$
The potential difference needed for electrolytic reduction of $Al_2O_3$ at $500^o C$ is at least ...... $V$.
$N_2 + 3H_2 \rightleftharpoons 2NH_3 \,;$ $K_1$
$N_2 + O_2 \rightleftharpoons 2NO\,;$ $K_2$
$H_2 + 2 O_2 \rightleftharpoons H_2O\,;$ $K_3$
The equilibrium constant $(K)$ of the reaction :
$2NH_3 + \frac{5}{2} \overset K \leftrightarrows 2NO + 3H_2O$
$X \rightleftharpoons Y + Z - - - - - - \left( 1 \right)$
$A \rightleftharpoons 2B - - - - - - \left( 2 \right)$
are in ratio of $9 :1$. If degree of dissociation of $X$ and $A$ be equal, then total pressure at equilibrium $(1)$ and $(2)$ are in the ratio
${H_2}\left( g \right)\,1atm\,|\,{H^ + }\left( {1M} \right)\,||\,C{u^{2 + }}\left( {1M} \right)\,|\,Cu\left( s \right)$
which of the following statements is true