- A$B$
- B$Li$
- ✓$Ne$
- D$F$
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$2 H _2( g )+2 NO ( g ) \rightarrow N _2( g )+2 H _2 O ( g )$
which following the mechanism given below:
$2 NO ( g ) \underset{ k _{-1}}{\stackrel{ k _1}{\rightleftharpoons}} N _2 O _2( g )$
$N _2 O _2( g )+ H _2( g ) \stackrel{ k _2}{\rightleftharpoons} N _2 O ( g )+ H _2 O ( g )$
$N _2 O ( g )+ H _2( g ) \stackrel{ k _3}{\rightleftharpoons} N _2( g )+ H _2 O ( g )$
(fast equilibrium)
(slow reaction)
(fast reaction)
The order of the reaction is
(Molar mass of $Fe =56\, g\, mol ^{-1}$ )
$A.$ $E _{\text {cell }}$ is an intensive parameter.
$B.$ A negative $E^{\Theta}$ means that the redox couple is a stronger reducing agent than the $H ^{+} / H _2$ couple.
$C.$ The amount of electricity required for oxidation or reduction depends on the stoichiometry of the electrode reaction.
$D.$ The amount of chemical reaction which occurs at any electrode during electrolysis by a current is proportional to the quantity of electricity passed through the electrolyte.