MCQ
Which $C-$atoms is the most electronegative in this structure $\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} $
- ✓$I$
- B$II$
- C$III$
- DAll are equal electronegative
✓
Answer
Correct option: A.
$I$
a
$\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} $
$\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} $
Elecronegativity $\propto$ $s$-character.
In $sp$ hybrid orbitals, $s$ character $=50\, \%$
and in $sp ^3$ hybrid orbitals, $s$ character $=33.3 \,\%$
Thus, option $I$ is the most electronegative.
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