STD 11 - 7. Redox reactions — NEET STD 11 Science — Question

$CH_4(g) +2O_2(g)  \rightarrow  CO_2(g)+2H_2O(l)\,;$  $\Delta H= -890 \,kJ$

$CO_2(g)  \rightarrow  C($graphite$) + O_2(g) \,;$   $\Delta H= 393 \,kJ$

$2H_2O(l)  \rightarrow  2H_2(g) + O_2(g) \,;$  $\Delta H= 571 \,kJ$

$2H_2(g) \rightarrow  4H(g)\, ;$  $\Delta H= 871\, kJ$

$C($graphite$)  \rightarrow  C(g)\, ;$  $\Delta H= 716\, kJ$

Ethanol $\xrightarrow{{PB{r_3}}}X\,\xrightarrow{{alc.\,KOH}}\,Y$$\,\xrightarrow[{(ii)\,{H_2}O\,,\,heat}]{{(i)\,{H_2}S{O_4},\,room\,\,temperature}}Z$

the product $Z$ is

To make it chiral compound the attack should be on which carbon atom