- ✓trans $-[Co(NH_3)_4 Cl_2]^+$
- B$[Cr(H_2O)_6]^{3+}$
- Ccis $- [Co(NH_3)_2 (en)_2 ]$
- Dtrans $-[Co(NH_3)_2 (en)_2]^{3+}$
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$(I)$ the highest oxidation state of iron is $+ 6$ in $K_ 2FeO_4$
$(II)$ that the iron shows $+ 2$ oxidation state with six electrons in the $3d$ orbitals
$(III)$ the common oxidation state of iron is $+3$ with five unpaired electrons in $3d$ orbital
${E^0}_{F{e^{3 + }}/F{e^{2 + }}}$ $=$ $ + 0.77\;V$
${E^0}_{S{n^{2 + }}/Sn} = - 0.14\;V$ Under standard conditions the potential for the reaction $S{n_{(s)}} + 2F{e^{3 + }}(aq) \to 2F{e^{2 + }}(sq) + S{n^{2 + }}(aq)$ is ............ $\mathrm{V}$
$C{O_{2(s)}} + {H_{2(g)}} \rightleftharpoons C{O_{(s)}} + {H_2}O(g)\,;\,{K_1}$
$C{O_{2(s)}} + CO(g) \rightleftharpoons C{O_{(s)}} + C{O_2}(g)\,;\,{K_2}$
Calculate the equilibrium for the reaction
$C{O_{2(s)}} + {H_2}(g) \rightleftharpoons CO(g) + {H_2}O(g)\,$
$2 A ( g ) \rightleftharpoons A _{2}( g )$
at $400\, K$ has $\Delta G ^{\circ}=+25.2\, kJ mol ^{-1}$.
The equilibrium constant $K _{ C }$ for this reaction is $...... \times 10^{-2}$. (Round off to the Nearest integ $\left[\right.$ Use $: R=8.3\, J mol ^{-1} K ^{-1}, \ln 10=2.3$
$\left.\log _{10} 2=0.30,1\, atm =1\, bar \right]$
$[$ antilog $(-0.3)=0.501]$