Where $kd =$ Dissociation constant
- A$[Cu(CN)_2]^-; Kd = 1 \times 10^{-16}$
- B$[Fe(CN)_6^-]^{-4} ; Kd = 1 \times 10^{-37}$
- ✓$[Fe(CN)_6]^{-3} ; Kd = 1 \times 10^{-44}$
- D$[Ag(CN)_2]^-; Kd = 1 \times 10^{-20}$
Where $kd =$ Dissociation constant
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$(I)$ ${P_4} + S{O_2}C{l_2} \to $
$(II)$ ${P_4} + SOC{l_2} \to $
$(III)$ $PC{l_5} + S{O_2} \to $
$(IV)$ $PC{l_5} + {C_2}{H_5}OH \to $
| Column $-I$ (various solutions) | Column $-II$ (Their freezing point ) | ||
| $a$ | $0.1\,M\, BaCl_2$ solution | $p$ | $271\,K$ |
| $b$ | $0.1\,M\, NaCl$ solution | $q$ | $270\, K$ |
| $c$ | $0.1\,M\, K_3 [Fe(CN)_6]$ solution | $r$ | $268\, K$ |
| $d$ | $0.1\,M\, Al_2 (SO_4)_3$ solution | $s$ | $269\, K$ |
Given : Freezing point of $0.1\,M$ sucrose solution $= 272\,K$ and $F.pt.$ of water $= 273\,K$
Which of the following option show correct matches ? (assume, molarity=molality)

$F_{2(g)} + 2e^- \rightarrow 2F^-_{(aq)}\, ;$ $E^o = + 2.85\, V$
$Cl_{2(g)} + 2e^- \rightarrow 2Cl^-_{(aq)}\, ;$ $E^o = + 1.36\, V$
$Br_{2(l)} + 2e^- \rightarrow 2Br^-_{(aq)}\, ;$ $E^o = + 1.06\, V$
$I_{2(s)} + 2e^- \rightarrow 2I^-_{(aq)}\, ;$ $E^o = + 0.53\, V$
The strongest oxidising and reducing agents respectively are