A carbonyl compound ${P}$, which gives positive iodoform test, undergoes reaction with $\mathrm{MeMgBr}$ followed by dehydration to give an olefin ${Q}$. Ozonolysis of ${Q}$ leads to a dicarbonyl compound ${R}$, which undergoes intramolecular aldol reaction to give predominantly ${S}$.
${P} \xrightarrow[\substack{\text { 2. } \mathrm{H}^{+}, \mathrm{H}_2 \mathrm{O} \\ \text { 3. } \mathrm{H}_2 \mathrm{SO}_4, \Delta}]{\text { 1. MeMgBr }}Q \xrightarrow[\text { 2. } \mathrm{Zn}, \mathrm{H}_2 \mathrm{O}]{1 . \mathrm{O}_3} {R} \xrightarrow[\text { 2. } \Delta]{1 . \mathrm{OH}^{-}} {S}$
$1.$ The structure of the carbonyl compound ${P}$ is
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$2.$ The structures of the products ${Q}$ and ${R}$, respectively, are
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$3.$ The structure of the product ${S}$ is
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Give hte answer question $1,2$ and $3.$
