MCQ
Which compound has bond angle nearly to $90^\circ $
- A${H_2}O$
- ✓${H_2}S$
- C$N{H_3}$
- D$C{H_4}$
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The possible reagents are :
$(I)\, 2Na/liq.NH_3$ $(II)\, H_2 /Pd/CaCO_3$ (quinoline) $(III)\, 2H_2 / Pd /C$
The correct statement with respect to the above conversion is/are

