- AAcetone
- BAlcohol
- ✓Methane
- DEthane
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$\Delta_{ I } G ^{\circ}=-9.478\, kJ\, mol ^{-1}$
If we start the reaction in a closed container at $495\, K$ with $22$ millimoles of $A ,$ the amount of $B$ is the equilibrium mixture is millimoles ..............
(Round off to the Nearest Integer).
$\left[ R =8.314 J mol ^{-1} K ^{-1} ; \ell n 10=2.303\right]$
$P : 10\ ml, 0.1\ M\ NaOH + 5\ ml, 0.1\ M\ HCl$
$Q : 10\ ml, 0.1\ M\ NaOH + 15\ ml, 0.1\ M\ CH_3COOH$
$R : 10\ ml, 0.1\ M\ NH_3 + 10\ ml, 0.1\ M\ NH_4Cl$
$S : 10\ ml, 0.05\ M\ NaF + 5\ ml, 0.1\ M\ HF$
Which of above solutions act as buffer
Assertion $(A) :$ Metallic character decreases and non-metallic character increases on moving from left to right in a period.
Reason $(R)$ $:$ It is due to increase in ionisation enthalpy and decrease in electron gain enthalpy, when one moves from left to right in a period.
In the light of the above statements, choose the most appropriate answer from the options given below :