Question
Which compound is optically active
✓
Answer
c
(c) $\mathop {C{H_3} - \mathop {\mathop {\mathop {C\,\,\, - }\limits_{|\,\,\,\,\,\,\,}^{|\,\,\,\,\,} }\limits^{H\,\,} }\limits_{\,N{H_2}} C{H_2} - C{H_3}}\limits_{} $
(c) $\mathop {C{H_3} - \mathop {\mathop {\mathop {C\,\,\, - }\limits_{|\,\,\,\,\,\,\,}^{|\,\,\,\,\,} }\limits^{H\,\,} }\limits_{\,N{H_2}} C{H_2} - C{H_3}}\limits_{} $
Secondary butyl amine is optically active.
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