- A$O - H.....S$
- B$S - H.....O$
- ✓$F - H.....F$
- D$O - H.....O$
electronegativity $ \propto \frac{1}{{{\rm{atomic}}\,{\rm{size}}}}$
So fluorine has maximum electronegativity and minimum atomic size.
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$(I){\mkern 1mu} C{H_3}CH_2^ - {\mkern 1mu} + {\mkern 1mu} \mathop {C{H_3}N{H_2}}\limits_{p{K_a} = 35} \rightleftharpoons \mathop {C{H_3}C{H_3}}\limits_{p{K_a} = 50} + C{H_3}N{H^ - }$
$(II){\mkern 1mu} {F^ - }{\mkern 1mu} + {\mkern 1mu} \mathop {{H_2}O}\limits_{p{K_a} = 15.7} \rightleftharpoons \mathop {HF}\limits_{p{K_a} = 3.2} + H{O^ - }$
$\begin{array}{*{20}{c}}
{HO - C = O\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{C{H_3} - C = C-C - H} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,N{H_2}\,\,\,\,\,Cl}
\end{array}$
is :