MCQ
Which does not undergo comproportionation reaction ?
- A${H_2}S\, + \,S{O_2}\, \to $
- B${I^ - }(aq.) + \,IO_3^ - (aq.) + {H^ + }(aq.)\, \to $
- ✓${K_2}Mn{O_4} + {H^ + }(aq.)\, \to $
- D$MnO_4^ - + M{n^{2 + }}(aq.)\, \to $
${{\text{I}}^ - }(aq.) + {\text{IO}}_3^ - (aq \cdot ) + {{\text{H}}^ + }(aq \cdot )\xrightarrow{{ComproP.}}{{\text{I}}_2} + {{\text{H}}_2}{\text{O}}$
${{\text{K}}_2}{\text{Mn}}{{\text{O}}_4} + {{\text{H}}^ + }(aq.)\xrightarrow{{disprop.}}{\text{KMn}}{{\text{O}}_4} + {\text{Mn}}{{\text{O}}_2} \downarrow $
${\text{MnO}}_4^ - (aq.) + {\text{M}}{{\text{n}}^{2 + }}(aq.)\xrightarrow{{ComproP.}}{\text{Mn}}{{\text{O}}_2} \downarrow $
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Assertion $A:$ Butan$-1-$ol has higher boiling point than ethoxyethane.
Reason $R:$ Extensive hydrogen bonding leads to stronger association of molecules.
In the light of the above statements, choose the correct answer from the options given below:
${C_6}{H_5}C{H_2}Br\xrightarrow[{(ii){H_3}{O^ + }}]{{(i)Mg.Ether}}X$
Product $X$ is
| Item $I$ | Item $II$ |
| $A$ Allosteric effect | $P$ Molecule binding to the active site of enzyme |
| $B$ Competitive inhibitor | $Q$ Molecule crucial for communication in the body |
| $C$ Receptor | $R$ Molecule binding to a site other than the active site of enzyme |
| $D$ Poison | $S$ Molecule binding to the enzyme covalently |