MCQ
Which does not undergo comproportionation reaction ?
- A${H_2}S\, + \,S{O_2}\, \to $
- B${I^ - }(aq.) + \,IO_3^ - (aq.) + {H^ + }(aq.)\, \to $
- ✓${K_2}Mn{O_4} + {H^ + }(aq.)\, \to $
- D$MnO_4^ - + M{n^{2 + }}(aq.)\, \to $
✓
Answer
Correct option: C.
${K_2}Mn{O_4} + {H^ + }(aq.)\, \to $
c
${{\text{H}}_2}{\text{S}} \uparrow + {\text{S}}{{\text{O}}_2} \uparrow \xrightarrow{{ComproP.}}{\text{S}} \downarrow + {{\text{H}}_2}{\text{O}}$
${{\text{H}}_2}{\text{S}} \uparrow + {\text{S}}{{\text{O}}_2} \uparrow \xrightarrow{{ComproP.}}{\text{S}} \downarrow + {{\text{H}}_2}{\text{O}}$
${{\text{I}}^ - }(aq.) + {\text{IO}}_3^ - (aq \cdot ) + {{\text{H}}^ + }(aq \cdot )\xrightarrow{{ComproP.}}{{\text{I}}_2} + {{\text{H}}_2}{\text{O}}$
${{\text{K}}_2}{\text{Mn}}{{\text{O}}_4} + {{\text{H}}^ + }(aq.)\xrightarrow{{disprop.}}{\text{KMn}}{{\text{O}}_4} + {\text{Mn}}{{\text{O}}_2} \downarrow $
${\text{MnO}}_4^ - (aq.) + {\text{M}}{{\text{n}}^{2 + }}(aq.)\xrightarrow{{ComproP.}}{\text{Mn}}{{\text{O}}_2} \downarrow $
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