- A$3s$
- B$2p$
- C$2s$
- ✓$1s$
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Statement I : $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ is a homoleptic complex whereas $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$is a heteroleptic complex.
Statement II : Complex $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ has only one kind of ligands but $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$has more than one kind of ligands.
In the light of the above statements, choose the correct answer from the options given below.

${N_2}\left( g \right) + {O_2}\left( g \right)\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}2NO\left( g \right)$
$C_0 = Ce^{-2.1×10^{-3}\ t}$ for the forward reaction and
$C_0'= C'e^{-4.2×10^{-4}\ t}$ for the backward reaction, hence $K_c$ for the above equilibrium is