Question
Which elements have the following electronic configurations? (Use only the periodic table.)
i. $1 s^2, 2 s^2, 2 p^5$
ii. $[\operatorname{Ar}] 4 s^2, 3 d^{10}, 4 p ^1$
iii. $[ Xe ] 6 s^2$
iv. $[ Xe ] 6 s^2, 5 d^1, 4 f ^7$
v. $[ Ar ] 4 s^1, 3 d^{10}$ (exception to rules)

Answer

  1. The outer electronic configuration of $1s^2, 2s^2, 2p^5$ is $2s^2, 2p^5$. Therefore, this element is a p-block element and belongs to the second period and group $17$. Thus, the element is fluorine, F.
  2. The outer electronic configuration of $[Ar]4s^2, 3d^{10}, 4p^1$ is $4s^2 4p^1$, therefore, it is a p-block element. It belongs to the fourth period and $13$ group. Therefore, the element is gallium, Ga.
  3. The outer electronic configuration of $[Xe]6s^2$ is $6s^2$, therefore, it is a s-block element and belongs to the sixth period and group $2$ of the periodic table.
Therefore, the element is barium, Ba.
  1. In the electronic configuration $[Xe]6s^2, 5d^1, 4f^7$ the electrons are in 4f shell, therefore, it is a f-block element and belongs to the sixth period and third group therefore, the element is gadolinium, Gd.
  2. The outer electronic configuration of $[Ar]4s^1, 3d^{10} is 4s^1, 3d^{10},$ therefore, it is a d-block element and belongs to the fourth period and group $11$. Therefore, the element is copper, Cu.

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