- AMetals
- BNon-metals
- Cp-block elements
- DTransitional elements
Explanation:
Transitional elements form coloured salts due to the presence of unpaired electrons of d-orbital.
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$\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}$ $\xrightarrow[{{\text{H}}_{2}}{{\text{O}}_{2}},\bar{O}\text{H}]{\text{B}{{\text{H}}_{3}},\text{THF}}(P)$ $\xrightarrow[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}]{\text{ Pyridinium Chloro Chromate }(\text{PCC})}$ $(Q)$
$\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}$ $\xrightarrow[NaB{{H}_{4}}\,,\,H{{O}^{\Theta }}]{Hg\,{{(OAc)}_{2}}\,,\,{{H}_{2}}O}(R)$ $\xrightarrow[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}]{\text{ Pyridinium Chloro Chromate }(\text{PCC})}$ $(S)$
| Rate Constant | Activation energy | |
| Step $1$ | $k_1$ | $E_{a_1} = 180\ kJ/mol$ |
| Step $2$ | $k_2$ | $E_{a_2} = 80\ kJ/mol$ |
| Step $3$ | $k_3$ |
$E_{a_3} = 50\ kJ/mol$ |
