Answer

(a): $\mathrm{Na}_x\left[\mathrm{Co}\left(\mathrm{NO}_2\right)_6\right]$

No. of $\mathrm{Na}: x(+1)+3+6(-1)=0$
$x+3-6=0$ or $x=3$

$\therefore \quad \mathrm{Na}_3\left[\mathrm{Co}\left(\mathrm{NO}_2\right)_6\right]$ is the correct formula.

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