MCQ
Which has the least bond angle
- A$N{H_3}$
- B$Be{F_2}$
- ✓${H_2}O$
- D$C{H_4}$
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$(I)\, (CH_3)_2P(CF_3)_3$ is non-polar and $(CH_3)_3P(CF_3)_2$ is polar molecule
$(II)\, CH_3 \widehat{P} CH_3$ bond angles are equal in $(CH_3)_3P(CF_3)_2$ molecule
$(III)\,PF_3$ will be more soluble in polar solvent than $SiF_4$

$Z\,\xrightarrow{{PC{l_5}}}\,X\,\xrightarrow[\Delta ]{{{\text{Alc}}{\text{.KOH}}}}\,Y\,\xrightarrow{{{H_2}O/{H^ \oplus }}}\,\mathop Z\limits_{{\text{(Major)}}} \,,\,\,Z$ is
| List-l(Compound) | List-ll (isomerism) |
| (a) $\left[ Co \left( NH _3\right)_6\right]\left[ Cr ( CN )_6\right]$ | i. Optical isomerism |
| (b) $\left[ Fe \left( H _2 O \right)_5 Cl \right] Br$ | ii. Coordination isomerism |
| (c) $\left[ PtCl _2\left( NH _3\right)_2\right]$ | iii. lonisation isomerism |
| (d) $K _3\left[ Co ( OX )_3\right]$ | iv. Geometrical isomerism |
