MCQ
Which has the maximum number of molecules among the following?
- A$44\; g\ CO_2$
- B$48\; g\ O_3$
- ✓$8\; g\ H_2$
- D$64\; g\ SO_2$
$64 g$ $SO_2=1$ mole
$44 \mathrm{g} \mathrm{CO}_2=1 \mathrm{mole}$
$48 \mathrm{g} O_2=48 / 32=1.5 \mathrm{mole}$
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$NH _{2} CN _{( s )}+\frac{3}{2} O _{2}( g ) \rightarrow N _{2( g )}+ O _{2}( g )+ H _{2} O _{(l)}$
is ............ $kJ$. (Rounded off to the nearest integer)
[Assume ideal gases and $\left. R =8.314\, J\, mol ^{-1} K ^{-1}\right]$

$(A)$ $\left[\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_2\right]$ $(B)$ $\left[\mathrm{Pt}(\mathrm{en})_2\right] \mathrm{Cl}_2$
$(C)$ $\left[\mathrm{Pt}(\text { en })_2 \mathrm{Cl}_2\right] \mathrm{Cl}_2$ $(D)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$