- ADiamond
- ✓Neon (Solid)
- C$KCl$
- DIce
In potassium chloride $( K C l )$ is containing an ionic bond.
In ice molecule containing hydrogen bond.
therefore, decreasing order of strong bond is as follows:-
Ionic $\,>\,$ Covalent $\,>\,$ Hydrogen $\,>\,$ Dipole-Dipole $\,>\,$ VanderWaal
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| $A/mol\,L^{-1}$ | $0.2$ | $0.2$ | $0.4$ |
| $B/mol\,L^{-1}$ | $0.3$ | $0.1$ | $0.05$ |
| $r_0/mol^{-1}s^{-1}$ | $5.0\times 10^{-5}$ | $5.0\times 10^{-5}$ | $1.4\times 10^{-4}$ |
image
$\mathop {C{H_3} - C{H_2} - N{H_2}}\limits_{\mathop 2\limits } \,$$\,\mathop {{{(C{H_3})}_2}NH}\limits_{\mathop 3\limits } $
$\mathop {C{H_3} - \mathop {\mathop C\limits^{||} }\limits^O - N{H_2}}\limits_4 $
$(I)\, (CH_3)_2P(CF_3)_3$ is non-polar and $(CH_3)_3P(CF_3)_2$ is polar molecule
$(II)\, CH_3 \widehat{P} CH_3$ bond angles are equal in $(CH_3)_3P(CF_3)_2$ molecule
$(III)\,PF_3$ will be more soluble in polar solvent than $SiF_4$