- A${H^ - }$
- B${F^ - }$
- C$B{r^ - }$
- ✓${I^ - }$
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(image) $\mathop {\xrightarrow{{CHC{l_3}/KOH}}}\limits_{heat} $ Intermediate $\mathop {\xrightarrow{{HCl}}}\limits_{300\,K} $ $X$
$P : 10\ ml, 0.1\ M\ NaOH + 5\ ml, 0.1\ M\ HCl$
$Q : 10\ ml, 0.1\ M\ NaOH + 15\ ml, 0.1\ M\ CH_3COOH$
$R : 10\ ml, 0.1\ M\ NH_3 + 10\ ml, 0.1\ M\ NH_4Cl$
$S : 10\ ml, 0.05\ M\ NaF + 5\ ml, 0.1\ M\ HF$
Which of above solutions act as buffer
$C{O_2} + 2{H_2}O\, \rightleftharpoons {H_3}{O^ + } + HCO_3^ - $
for which the equilibrium constant is $3.8 \times 10^{-7}$ and $pH = 6.0$. The ratio of $[HCO_3^- ]$ to $[CO_2]$ would be :-
$(II)\,\,\,{{H}_{2}}C=CH-C{{H}_{2}}-\overset{+}{\mathop{C}}\,H-C{{H}_{3}}$
$(III)\,\,\,\begin{matrix}
\,\,\,\,\,C{{H}_{3}}\, \\
|\, \\
{{H}_{3}}C-C-\overset{+}{\mathop{C}}\,{{H}_{2}} \\
|\, \\
\,\,\,C{{H}_{3}} \\
\end{matrix}$