MCQ
Which is correct oxidation state of lead
- ✓$+ 2$, $+ 4$
- B$+ 1$, $+ 2$
- C$+ 3$, $+ 4$
- D$4$
$+2$ oxidation state which is lower oxidation state due to inert pair effect(stable oxidation state for lead).
$+4$ oxidation state which is Higher oxidation state
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| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{B}_2$ | $(p)$ Paramagnetic |
| $(B)$ $\mathrm{N}_2$ | $(q)$ Undergoes oxidation |
| $(C)$ $\mathrm{O}_2^{-}$ | $(r)$ Undergoes reduction |
| $(D)$ $\mathrm{O}_2$ | $(s)$ Bond order $\geq 2$ |
| $(t)$ Mixing of ' $\mathrm{s}$ ' and ' $\mathrm{p}$ ' orbitals |