MCQ
Which is correct
- A$Z = 72 : p$ block
- B$Z = 91 : d$ block
- C$Z = 85 : f$ block
- ✓None
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$(a)$ Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.
$(b)$ Each boron atom is in sp $^{2}$ hybridized state.
$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.
$(d)$ Diborane is a planar molecule.
The option with correct statement(s) is :