MCQ
Which is correctly matched
- A(figure) - Heterocyclic compound
- B(figure) - only two types of carbon and hydrogen present
- C(figure) - Homocyclic compound
- ✓(figure) - Equal number of $1^o, 2^o$ and $3^o$
✓
Answer
Correct option: D.
(figure) - Equal number of $1^o, 2^o$ and $3^o$
d
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have highest bond dissociation enthalpy?
$(X){{C}_{4}}{{H}_{7}}OCl\xrightarrow{N{{H}_{3}}}{{C}_{4}}{{H}_{9}}ON\xrightarrow[KOH]{B{{r}_{2}}}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}};$ Compound $(X)$ is
→When an acyl chloride is heated with $Na$ salt of a carboxylic acid, the product is
→Which of the following reaction is called as wurtz fittig reaction ?
Consider the following single step reaction in gas phase at constant temperature.
→$2 \mathrm{~A}_{(\mathrm{g})}+\mathrm{B}_{(\mathrm{g})} \rightarrow \mathrm{C}_{(\mathrm{g})}$
The initial rate of the reaction is recorded as $r_1$ when the reaction starts with $1.5 \mathrm{~atm}$ pressure of $\mathrm{A}$ and $0.7 \mathrm{~atm}$ pressure of B. After some time, the rate $r_2$ is recorded when the pressure of $C$ becomes $0.5 \mathrm{~atm}$. The ratio $r_1: r_2$ is $\qquad$ $\times 10^{-1}$.
(Nearest integer)
Complete removal of both the axial ligands (along the $z-$ axis) from an octahedral complex leads to which of the following splitting patterns? (relative orbital energies not on scale)
→The Crystal Field Stablilisation Energy $(CFSE)$ for $\left[\mathrm{CoCl}_{6}\right]^{4-}$ is $18000 \;\mathrm{cm}^{-1}$. The $CFSE$ for $\left[\mathrm{CoCl}_{4}\right]^{2-}$ will be ......${cm}^{-1}$
→Consider the reactions.
→$(i)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}OH}}$ $ (CH_3)_2CH - CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}O^-}} $ $(CH_3)_2CH - CH_2OC_2H_5 + Br^-$
The mechanisms of reactions $(i)$ and $(ii)$ are respectively
Aqueous solutions of two compounds $M_1 -O -H$ and $M_2 -O -H$ are prepared in two different beakers. If, the electronegativity of $M_1$ = $3.4$, $M_2$ = $1.2$, $O$ = $3.5$ and $H$ = $2.1$, then the nature of two solutions will be respectively
→On reduction with hydrogen, $3.6 \,g$ of an oxide of metal left $3.2 \,g$ of metal. If the vapour density of metal is $32$, the simplest formula of the oxide would be
→