- A

- B

- ✓

- D






Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
(Given: specific rotations of ($+$)-sucrose, ($+$)-maltose, $L$-($-$)-glucose anc. $+(+)$-fructose in aqueous solution are $+66^{\circ},+140^{\circ},-52^{\circ}$ and $+92^{\circ}$, respectively)
($A$) 'invert sugar' is prepared by acid catalyzed hydrolysis of maltose
($B$) . 'invert sugar' is an equimolar mixture of $D$-($+$)-glucose and $D$-($-$)-fructose
($C$) specific rotation of 'invert sugar' is $-20^{\circ}$
($D$) on reaction with $\mathrm{Br}_2$ water, 'invert sugar' forms saccharic acid as one of the products
$A\,\xrightarrow{{H{g^{2 + }}\,/\,{H^ + }}}B\,\xrightarrow{{NaB{H_4}}}C\,\xrightarrow[{conc.\,\,HCl}]{{ZnC{l_2}}}$ Turbidity within $5$ minutes.
Consider the following reactions $‘A’$ is
${\text{2PQ}} \rightleftharpoons {{\text{P}}_2}{\text{ + }}{{\text{Q}}_2}\,;\,\,\,\,{{\text{K}}_1}{\text{ = 2}}{\text{.5 }} \times \,{\text{1}}{{\text{0}}^5}\,$
${\text{PQ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,;\,\,\,\,{{\text{K}}_2}{\text{ = 5 }} \times \,{\text{1}}{{\text{0}}^{ - 3}}\,$
The value of equilibrium constant for reaction
$\frac{1}{2}{{\text{P}}_2}{\text{ + }}\frac{1}{2}{{\text{Q}}_2}{\text{ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,$ is
