MCQ
Which is most suitable compound for acetylation?
- A$CH _3 CONH _2$
- B$CH _3 COOH$
- ✓$\left( CH _3 CO \right)_2 O$
- D$CH _3 COOC _2 H _5$
✓
Answer
Correct option: C.
$\left( CH _3 CO \right)_2 O$
c
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The aqueous solution containing which one of the following ions will be colourless
Chlorination of toluene in the presence of light and heat followed by treatment with aqueous $NaOH $ gives
→Ammonium chloride used in dry cell acts as
In which reaction racemic mixture is not obtained ?
Redox reactions play a pivotal role in chemistry and biology. The values of standard redox potential ( $\mathrm{E}^{\circ}$ ) of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their $E^{\circ}$ ($V$ with respect to normal hydrogen electrode) values.
→$\mathrm{I}_2+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{I}\ \ \ \mathrm{E}^{\circ}=0.54 $
$\mathrm{Cl}_2+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cl}^{-} \ \ \ \mathrm{E}^{\circ}=1.36 $
$\mathrm{Mn}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+} \ \ \ \mathrm{E}^{\circ}=1.50 $
$\mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+} \ \ \ \mathrm{E}^{\circ}=0.77 $
$\mathrm{O}_2+4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_2 \mathrm{O} \ \ \ \mathrm{E}^{\circ}=1.23$
$1.$ Among the following, identify the correct statement.
$(A)$ Chloride ion is oxidized by $\mathrm{O}_2$
$(B)$ $\mathrm{Fe}^{2+}$ is oxidized by iodine
$(C)$ Iodide ion is oxidized by chlorine
$(D)$ $\mathrm{Mn}^{2+}$ is oxidized by chlorine
$2.$ While $\mathrm{Fe}^{3+}$ is stable, $\mathrm{Mn}^{3+}$ is not stable in acid solution because
$(A)$ $\mathrm{O}_2$ oxidises $\mathrm{Mn}^{2+}$ to $\mathrm{Mn}^{3+}$
$(B)$ $\mathrm{O}_2$ oxidises both $\mathrm{Mn}^{2+}$ and $\mathrm{Fe}^{2+}$ to $\mathrm{Fe}^{3+}$
$(C)$ $\mathrm{Fe}^{3+}$ oxidizes $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$
$(D)$ $\mathrm{Mn}^{3+}$ oxidises $\mathrm{H}_2 \mathrm{O}$ to $\mathrm{O}_2$
$3.$ Sodium fusion extract, obtained from aniline, on treatment with iron $(II)$ sulphate and $\mathrm{H}_2 \mathrm{SO}_4$ in presence of air gives a Prussian blue precipitate. The blue colour is due to the formation of
$(A)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$ $(B)$ $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$
$(C)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$ $(D)$ $\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$
Give the answer question $1,2$ and $3.$
Suppose that an alkaline dry cell was manufactured using cadmium metal rather than $Zn$ . What effect would this have on the standard emf of the cell. The standard reduction potential $E_{C{d^{2 + }}/Cd}^o = - 0.40\,V$
→while $E_{Z{n^{2 + }}/Zn}^o = - 0.76\,V$
Phosphonic acid is
What is the major product of above Friedel-Craft reaction ?
| Column $-I$ (various solutions) |
Column $-II$ (Their freezing point ) |
||
| $a$ | $0.1\,M$ $BaCl_2$ solution | $p$ | $271\,K$ |
| $b$ | $0.1\,M$ $NaCl$ solution | $q$ | $270\,K$ |
| $c$ | $0.1\,M\, K_3 [Fe(CN)_6]$ solution | $r$ | $268\,K$ |
| $d$ | $0.1\,M\, Al_2 (SO_4)_3$ solution | $s$ | $269\,K$ |
Given : Freezing point of $0.1\,M$ sucrose solution $= 272\,K$ and $F.pt.$ of water $= 273\,K$
Which of the following option show correct matches ?
The Vant Hoff factor for a dilute solution $\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right].$
→