Which is smaller, 64^ or 64^ ? - Vidyadip

MCQ

Which is smaller, $\sin 64^{\circ}$ or $\cos 64^{\circ}$ ?

A
$\cos 64^{\circ}$
B
$\sin 64^{\circ}$
C
cannot be compared
D
both are equal

✓

Answer

(a) $\cos 64^{\circ}$
Explanation: In quadrant $I , \sin \theta$ is increasing.
Now, $\cos 64^{\circ}=\cos \left(90^{\circ}-26^{\circ}\right)=\sin 26^{\circ}$.
Clearly, $\sin 26^{\circ}<\sin 64^{\circ} \Rightarrow \cos 64^{\circ}<\sin 64^{\circ}$

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