- ✓Urea
- BMethanol
- CAmmonia
- DSulphuric Acid
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$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$
$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$ The $\Delta H ^\theta$ for the reaction $......$.$C ($ graphite $)+\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ is

[Given: Solubility product of $PbSO _4\left(K_{s p}\right)=1.6 \times 10^{-8}$. For $H _2 SO _4, K_{a l}$ is very large and $\left.K_{a 2}=1.2 \times 10^{-2}\right]$


$(1)$ An electron in an orbital of high angular momentum stays away from the nucleus than an electron in the orbital of lower angular momentum.
$(2)$ For a given value of the principal quantum number, the size of the orbit is inversely proportional to the azimuthal quantum number
$(3)$ According to wave mechanics, the ground state angular momentum is equal to $\frac {h}{2\pi }$
$(4)$ The plot of $\Psi \,\,Vs\,\,r$ for various azimuthal quantum numbers, shows peak shifting towards higher $r$ value