MCQ
Which is the $CORRECT$ relation of bond angles?
- A$NH_3 > (CH_3)_3N > (SiH_3)_3N$
- ✓$(SiH_3)_3N > (CH_3)_3N > NH_3$
- C$NH_3 > (SiH_3)_3N > (CH_3)_3N$
- D$(CH_3)_3N > (SiH_3)_3N > NH_3$
✓
Answer
Correct option: B.
$(SiH_3)_3N > (CH_3)_3N > NH_3$
b
$\mathrm{NH}_{3} \quad \mathrm{sp}^{3}: 107^{o}$
$\mathrm{NH}_{3} \quad \mathrm{sp}^{3}: 107^{o}$
$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N} \quad \mathrm{sp}^{3}: 108^{o}$ -bulky have more
repulsion than smaller $H$
$-\left(\mathrm{SiH}_{3}\right)_{3} \mathrm{N} \cdot \mathrm{sp}^{2}: 120^{o}\, \mathrm{LP}$ of $\mathrm{N}$ engages in back
bonding with empty $d$ orbitals of $Si$
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