MCQ
Which $L$ -sugar on oxidation gives an optically active dibasic acid
- ✓
- B
- C
- D
✓
Answer
Correct option: A.
a
Any sugar will be optically active when it does not have any plane of symmetry.
Any sugar will be optically active when it does not have any plane of symmetry.
As only $(a)$ and $(d)$ are $L$-sugar, $(b)$ and $(c)$ are $D$-sugar after oxidation.
$(a)$ (Refer to Image $1$)
As the product do not superimpose in its mirror image.
$(d)$ (Refer to Image $2$)
As it has plane of symmetry.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Reactant $P$ gives products $Q$ or $R$.
→The possible reagents are :
$(I)\, 2Na/liq.NH_3$ $(II)\, H_2 /Pd/CaCO_3$ (quinoline) $(III)\, 2H_2 / Pd /C$
The correct statement with respect to the above conversion is/are
If $p{K_b}$ for fluoride ion at ${25\,^o}C$ is $10.83$, the ionisation constant of hydrofluoric acid in water at this temperature is
→Meso-tartaric acid is optically inactive due to the presence of
How many different types of $OBO$ angles are there in sodium peroxoborate ?
→The total number of electrons in all bonding molecular orbitals of $O_{2}^{2-}$ is $....\,.$
→(Round off to the Nearest Integer).
Solubility product is
Given : $I$ and $II$ are
→Under hydrolytic conditions, the compounds used for preparation of linear polymer and for chain termination, respectively, are
From the given sets of quantum numbers the one that is inconsistent with the theory is
The pH of mixture of $50 mL \frac{ N }{10} NaOH$ and 10 ml $\frac{ N }{2} H _2 SO _4$ is :
→