MCQ
Which molecule has the highest bond order
- ✓${N_2}$
- B$L{i_2}$
- C$H{e_2}$
- D${O_2}$
$N _2$ has the highest bond order which is $3 .$
$Li _2, He _2$ and $O _2$ have bond orders $1,0$ and $2$ respectively.
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$\begin{array}{*{20}{c}}
{R = - CH - Cl}\\
{|\,\,}\\
{\,\,\,\,C{H_3}}
\end{array}\,\,\,\,,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{S = - CH - Cl}\\
{|\,\,}\\
{Br}
\end{array}$
$\mathrm{X}_2(g) \rightleftharpoons 2 \mathrm{X}(g)$
The standard reaction Gibbs energy, $\Delta_r G^{\circ}$, of this reaction is positive. At the stiur of the reaction, there is one mole of $X_2$ and no $X$. As the reaction proceeds, the number of roles of $X$ formed is given by $\beta$. Thus, $\beta_{\text {equitibrium }}$ is the number of moles of $\mathrm{X}$ formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given : $R=0.083 \mathrm{~L} \mathrm{bar}^{-1} \mathrm{~mol}^{-1}$ )
($1$) The equilibrium constant $K_P$ for this reaction at $298 \mathrm{~K}$, in terms of $\beta_{\text {equilibs, um }}$, is
($A$) $\frac{8 \beta_{\text {equilibrium }}^2}{2-\beta_{\text {equilibrium }}}$ ($B$) $\frac{8 \beta_{\text {equititrium }}^2}{4-\beta_{\text {equilibrium }}^2}$ ($C$) $\frac{4 \beta_{\text {equilibrium }}^2}{2-\beta_{\text {equilibrium }}}$ ($D$) $\frac{4 \ell_{\text {equitibrium }}^2}{4-\beta_{\text {equilibrium }}^2}$
($2$) The $INCORRECT$ statement among the following, for this reaction, is
($A$) Decrease in the total pressure will result in formation of more moles of gaseous $\mathrm{X}$
($B$) At the start of the reaction, dissociation of gaseous $\mathrm{X}_2$ takes place spontaneously
($C$) $\beta_{\text {equilibrium }}=0.7$
($D$) $\quad K_c<1$
Given the answer question ($1$) and ($2$)
Given $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 4=0.6021$