Download App

PART - 1 CH - 6 Equilibrium — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistryPART - 1 CH - 6 Equilibrium1 Mark
MCQ
Which of the following aqueous solution of compound have maximum pH?
  • A
    $NH _4 Cl$
  • B
    $Na _2 CO _3$
  • ✓
    NaOH
  • D
    NaCl
✓

Answer

Correct option: C.
NaOH
C

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from PART - 1 CH - 6 Equilibrium→PART - 1 CH - 6 Equilibrium — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Which of the following has the least energy
→
The aqueous solution of which of the following salt has the lowest $pH$
→
Amongst the following elements, whose electronic configurations are given below, the one having the highest ionization enthalpy is:
→
Identify correct stability order of resonating structures ?
→
The atomic weight of an element is double its atomic number. If there are four electrons in $2p$ orbital, the element is
→
A buffer solution has equal volumes of $0.2\,M\,N{H_4}OH$ and $0.02\,M\,N{H_4}Cl$. The $p{K_b}$ of the base is $5$. The $pH$ is
→
Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$

Assertion $A :$- Carbon forms two important oxides $- CO$ and $CO _2 . CO$ is neutral whereas $CO _2$ is acidic in nature.

Reason $R :$- $CO _2$ can combine with water in a limited way to form carbonic acid, while $CO$ is sparingly soluble in water.

In the light of the above statements, choose the most appropriate answer from the options given below :-

→
Which is not true about borax?
→
The enthalpy of neutralisation of $NH_4OH$ with $HCl$ is $-51 .46\,kJ\,mol^{-1}$ and the enthalpy of neutralisation of $NaOH$ with $HCl$ is $-55. 90\,kJ\,mol^{-1}.$ The enthalpy of ionisation of $NH_4OH$ is......$kJ\,mol^{-1}$
→
$C{u^{2 + }}$ will have the following electronic configuration
→