- ✓$DC{H_2}C{H_2}C{H_2}Cl$
- B$C{H_3}C{H_2}CHDCl$
- C$C{H_3}CHDC{H_2}C{H_2}Cl$
- D$C{H_2}CHClC{H_2}D$
$C{H_3} - C{H_2} - \mathop {\mathop {\mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,\,} }\limits_{Cl} }\limits^{|\,\,\,\,\,} }\limits^{H\,\,\,\,} - D$; $C{H_3} - \mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,}^{|\,\,\,\,} }\limits_{D\,\,}^{H\,\,} - C{H_2} - C{H_2} - Cl$
$C{H_3} - \mathop {\mathop {{C^ * }}\limits_{|\,\,\,\,}^{|\,\,\,\,} }\limits_{Cl\,\,}^{H\,\,} - C{H_2}D$
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$NH_3{_{(g)}}\ \rightleftharpoons \ \frac {1}{2} {N_2}_{(g)} + \frac {3}{2} {H_2}_{(g)}$ ; $K_P$
The degree of dissociation $(\alpha )$ of $NH_3$ is related to total equilibrium pressure $(P^o )$ as

Assertion $(A)$: Cis form of alkene is found to be more polar than the trans form
Reason $(R)$: Dipole moment of trans isomer of $2$-butene is zero.
In the light of the above statements, choose the correct answer from the options given below :
