MCQ
Which of the following elements outermost orbit's last electron has magnetic quantum number $m=0$ ?
- ✓$Na$
- B$O$
- C$Cl$
- D$N$
For $Na ,\, 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
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$2MnO_4^ - + 5{C_2}O_4^{2 - } + 16{H^ + } \to 2M{n^{2 + }} + 10C{O_2} + 8{H_2}O$
Here $20\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to
(IMAGE)
$[A]$ $I$ and $III$ follow $\mathrm{S}_{\mathrm{N}} 1$ mechanism
$[B]$ $I$ and $II$ follow $\mathrm{S}_{\mathrm{N}} 2$ mechanism
$[C]$ Compound $IV$ undergoes inversion of configuration
$[D]$ The order of reactivity for $I$, $III$ and $IV$ is: $IV$ $>$ $I$ $>$ $III$