MCQ
Which of the following equations has two distinct real roots?
  • $x^2+x-5=0$
  • B
    $5 x^2-3 x+1=0$
  • C
    $4 x^2-3 x+1=0$
  • D
    $x^2+x+5=0$

Answer

Correct option: A.
$x^2+x-5=0$
In equation $x^2+x-5=0$
$a=1, b=1, c=-5$
$\therefore b^2-4 a c$
$=(1)^2-4 \times 1 \times(-5)$
$=1+20$
$=21$
Since $b^2-4 a c>0$
therefore, $x^2+x-5=0$ has two distinct roots.

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