- A$H_2O$
- B$F_2O$
- ✓$Cl_2O$
- D$H_2S$
Oxygen difluoride is a chemical element having the symbol $F_2 O$. The bond angle of water is equal to $102^{\circ}$ and it does not have the largest bond angle. Hence, option $(B)$ is incorrect.
Among the given compounds, the $Cl _2 O$ has the largest bond angle and which is equal to $109.5^{\circ}$. The largest bond angle of chlorine monoxide is because of the presence of large lone pair - bond pair repulsion. And it will increase the bond angle of chlorine monoxide. And this type of repulsion also depends upon the electronegativity. Hence, option $(C)$ is correct.
Hydrogen sulphide is a chemical element having the symbol $H _2 S$. The bond angle of water is equal to $90^{\circ}$ and it does not have the largest bond angle. Hence, option $(D)$ is incorrect.
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$A : 1s^2\, 2s^2\, 2p^6$
$B : 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^3$
$C : 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^5$
$2 NO _{( g )}+ O _{2}( g ) \rightleftarrows 2 NO _{2}( g )$
The reaction occurring as above comes to equilibrium under a total pressure of 1 atom. Analysis of the system shows that $0.6 mol$ of oxygen are present at equilibrium. The equilibrium constant for the reaction is $.........$(Nearest integer).