- A$2\;g$ atom of nitrogen
- ✓$3 \times {10^{23}}$ atoms of $C$
- C$1$ mole of $S$
- D$7.0\;g$ of $Ag$
$(b)$ $6 \times {10^{23}}$ atoms of $C$ has mass $ = 12\,gm$
$3 \times {10^{23}}$ atoms of $C$ has mass $ = \frac{{12 \times 3 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 6\,gm$
$(c)$ $1$ mole of $S$ has mass $= 32\,gm$
$(d)$ $7.0\,gm$ of $Ag$
So, lowest mass = $6\,gm$ of $C$.
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$(I) \,C{H_3}CH = C{H_2} + HBr\xrightarrow{{peroxide}}$
$(II)\, C{H_3}CH = C{H_2} + HBr\xrightarrow{{CC{l_4}}}$
$(III)\, C{H_3}C{H_2}C{H_3} + B{r_2}\xrightarrow{{hv}}$
$(IV)\,C{H_3}CH = C{H_2} + B{r_2}\xrightarrow{{CC{l_4}}}$
$H - C\, \equiv CH\,\xrightarrow[{(ii)\,C{H_3}C{H_2}Br}]{{(i)\,NaN{H_2}\,/\,liq.\,N{H_3}}}\,X$
$\xrightarrow[{(ii)\,C{H_3}C{H_2}Br}]{{(i)\,NaN{H_2}\,/\,liq.\,N{H_3}}}\,Y$
$X$ and $Y$ are