- A$NO^-_3$
- ✓$SO^{2-}_3$
- C$BO^{3-}_3$
- D$CO^{2-}_3$
This type of bonding is called p $\pi-\mathrm{p} \pi$ or $\mathrm{p} \pi-\mathrm{d} \pi$ depending on the orbital to which the electron pair is donated and from which the electron pair is donated.
In the above options $\mathrm{SO}_{3}^{-2}$ forms p $\mathrm{p} \pi-\mathrm{p} \pi$ bonding.
Hence option $\mathrm{B}$ is correct.
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| Compound | Weight $\%$ of $P$ | Weight $\%$ of $Q$ |
| $1$ | $50$ | $50$ |
| $2$ | $44.4$ | $55.6$ |
| $3$ | $40$ | $60$ |
$(A)$ If empirical formula of compound $3$ is $P_3 Q_4$, then the empirical formula of compound $2$ is $P_3 Q_5$.
$(B)$ If empirical formula of compound $3$ is $P _3 Q _2$ and atomic weight of element $P$ is $20$ , then the atomic weight of $Q$ is $45$ .
$(C)$ If empirical formula of compound $2$ is $PQ$, then the empirical formula of the compound $1$ is $P _5 Q _4$.
$(D)$ If atomic weight of $P$ and $Q$ are $70$ and $35$ , respectively, then the empirical formula of compound $1$ is $P _2 Q$.