MCQ
Which of the following have identical bond order?
- A$\ce{CN}^{-}$
- B$\ce{NO}^{+}$
- C$\ce{O_2^}$
- D$\ce{O_2^{2-}}$
✓
Answer
$\mathrm{CN}^{-}\ ($number of electrons $\left.=6+7+1=14\right) $
$\mathrm{NO}^{+}\ ($number of electrons $=7+8-1=14 )$
$\mathrm{O}_2^{-}\ ($number of electrons $\left.=8+8+1=17\right)$
$\mathrm{O}_2{ }^{2-} \ ($number of electrons $\left.=8+8+2=18\right)$
Thus, $\ce{CN}$ and $\ce{NO^+}$ because of the presence of same number of electrons, have same bond order.
$\mathrm{NO}^{+}\ ($number of electrons $=7+8-1=14 )$
$\mathrm{O}_2^{-}\ ($number of electrons $\left.=8+8+1=17\right)$
$\mathrm{O}_2{ }^{2-} \ ($number of electrons $\left.=8+8+2=18\right)$
Thus, $\ce{CN}$ and $\ce{NO^+}$ because of the presence of same number of electrons, have same bond order.
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