MCQ
Which of the following is a cyclic phosphate
- A${H_5}{P_3}{O_{10}}$
- B${H_6}{P_4}{O_{13}}$
- ✓${H_5}{P_5}{O_{15}}$
- D${H_7}{P_5}{O_{16}}$
Therefore only $H _5 P _5 O _{15}=\left( HPO _3\right)_5$ satisfies this.
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$(a)$ coordination number of $'N'$ is $3$ , and the structure is triagonal planar
$(b)$ formal charge on $N$ is $+1$
$(c)$ Average formal charge on $'O'$ is $-2/3$
$(d)$ Average bond order of $NO$ bond is $4/3$
$(e)$ All $NO$ bond lengths are identical
Correct code is