MCQ
Which of the following is a Lewis base
- A$NaOH$
- ✓$N{H_3}$
- C$BC{l_3}$
- DAll of these
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$\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}_2 \xrightarrow[\text { (iii) } \mathrm{HBr}{(iv) \mathrm{Mg}, ether, then \mathrm{HCHO} / \mathrm{H}_3 \mathrm{O}^{+}}]{{(i)BH_3}{\text { (ii) } \mathrm{H}_2 \mathrm{O}_2,{ }^{\text {(-) }} \mathrm{OH}}} \mathrm{A}$
$(A)\, CH_3 - CH_2 - C \equiv C^-$ $(B) \,CH_3 -CH_2 - S^-$
$(C) \,CH_3 - CH_2 - CO^-_2$ $(D)\, CH_3 -CH_2 - O^-$
| Expt. No. | $(A)$ | $(B)$ | Initial Rate |
| $1$ | $0.012$ | $0.035$ | $0.10$ |
| $2$ | $0.024$ | $0.070$ | $0.80$ |
| $3$ |
$0.024$ |
$0.035$ | $0.10$ |
| $4$ | $0.012$ | $0.070$ | $0.80$ |
The Gibbs free energy change for the above reaction at $298\, K$ is $x \times 10^{-1} \,k\,J\, mol ^{-1}$;
The value of $x$ is ..... [nearest integer]$\left [\text { Given : } E _{ Cu ^{2} / / Cu }=0.34\, V ; E _{ Sn ^{2} / Sn }^{\ominus}=-0.14 \,V ; F=96500\, C\, mol ^{-1}\right]$