MCQ
Which of the following is a second order differential equation?
- A$\left(y^{\prime}\right)^2+x=y^2$
- ✓$y^{\prime} y^{\prime \prime}+y=\sin x$
- C$y^{\prime \prime \prime}+\left(y^{\prime \prime}\right)^2+y=0$
- D$y^{\prime}=y^2$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List $I$ | List $II$ |
| $P$ $\quad\left(\frac{1}{y^2}\left(\frac{\cos \left(\tan ^{-1} y\right)+y \sin \left(\tan ^{-1} y\right)}{\cot \left(\sin ^{-1} y\right)+\tan \left(\sin ^{-1} y\right)}\right)^2+y^4\right)^{1 / 2}$ takes value | $1.\quad$ $\frac{1}{2} \sqrt{\frac{5}{3}}$ |
| $Q.\quad$ If $\cos x+\cos y+\cos z=0=\sin x+\sin y+\sin z$ then possible value of $\cos \frac{x-y}{2}$ is | $2.\quad$ $\sqrt{2}$ |
| $R.\quad$ If $\cos \left(\frac{\pi}{4}-x\right) \cos 2 x+\sin x \sin 2 x \sec x=\cos x \sin 2 x \sec x+$ $\cos \left(\frac{\pi}{4}+x\right) \cos 2 x$ then possible value of $\sec x$ is | $3.\quad$ $\frac{1}{2}$ |
| $S.\quad$ If $\cot \left(\sin ^{-1} \sqrt{1-x^2}\right)=\sin \left(\tan ^{-1}(x \sqrt{6})\right), x \neq 0$, then possible value of $x$ is | $4.\quad$ $1$ |
Codes: $ \quad P \quad Q \quad R \quad S $
$\left[\begin{array}{ccc}e^t & e^{-t}(\sin t-2 \cos t) & e^{-t}(-2 \sin t-\cos t) \\e^t & e^{-t}(2 \sin t+\cos t) & e^{-t}(\sin t-2 \cos t) \\e^t & e^{-t} \cos t & e^{-t} \sin t \end{array}\right]$ is invertible.