Download App

Linear Programming — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsLinear Programming1 Mark
Question
Which of the following is an essential condition in a situation for linear programming to be useful?
  1. Linear constraints
  2. Bottlenecks in the objective function
  3. Non - homogeneity
  4. Uncertainty
  5. None of the above
✓

Answer

  1. Linear constraints

Solution:

For linear programming, the constraints must be linear.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The slope of the tangent at $(x, y)$ to a curve passing through a point $(2, 1)$ is $\frac{{{x^2} + {y^2}}}{{2xy}}$, then the equation of the curve is
→
A line $l$ passing through the origin is perpendicular to the lines

$l_1:(3+ t ) \hat{ i }+(-1+2 t ) \hat{ j }+(4+2 t ) \hat{ k },-\infty< t <\infty $

$l_2:(3+2 t ) \hat{ i }+(3+2 t ) \hat{ j }+(2+ s ) \hat{ k },-\infty< s <\infty$

Then, the coordinate$(s)$ of the point$(s)$ on $l_2$ at a distance of $\sqrt{17}$ from the point of intersection of $l$ and $l_1$ is(are)

$(A)$ $\left(\frac{7}{3}, \frac{7}{3}, \frac{5}{3}\right)$ $(B)$ $(-1,,-1,0)$ $(C)$ $(1,1,1)$ $(D)$ $\left(\frac{7}{9}, \frac{7}{9}, \frac{8}{9}\right)$

→
$\int_{}^{} {\frac{{dx}}{{\sqrt {{x^2} - {a^2}} }}} $ equals
→
A particle moves in a straight line so that its velocity at any point is given by ${v^2} = a + bx$, where $a,b \ne 0$ are constants. The acceleration is
→
If $\int\limits_0^1 {\,\,\frac{{\ell n\,x}}{{\sqrt {1\,\, - \,\,{x^2}} }}} dx$ $= k\, \int\limits_0^\pi  {}  ln \,(1 + \cos \,x)\, dx$ then the value of $k$ is :
→
The shortest distance between lines $\mathrm{L}_1$ and $\mathrm{L}_2$, where $L_1: \frac{x-1}{2}=\frac{y+1}{-3}=\frac{z+4}{2}$ and $L_2$ is the line passing through the points $\mathrm{A}(-4,4,3) \cdot \mathrm{B}(-1,6,3)$ and perpendicular to the line $\frac{x-3}{-2}=\frac{y}{3}=\frac{z-1}{1}$, is
→
Let $f (\theta)=\sin \theta+\int_{-\pi / 2}^{\pi / 2}(\sin \theta+ t \cos \theta) f ( t ) dt$. Then the value of $\left|\int_{0}^{\pi / 2} f (\theta) d \theta\right|$ is
→
Let $E$ and $F$ be two independent events. The probability that exactly one of them occurs is $\frac{11}{25}$ and the probability of none of them occurring is $\frac{2}{25}$. If $P(T)$ denotes the probability of occurrence of the event $T$, then

$(A)$ $P(E)=\frac{4}{5}, P(F)=\frac{3}{5}$

$(B)$ $P(E)=\frac{1}{5}, P(F)=\frac{2}{5}$

$(C)$ $P(E)=\frac{2}{5}, P(F)=\frac{1}{5}$

$(D)$ $P(E)=\frac{3}{5}, P(F)=\frac{4}{5}$

→
If a line makes angles $\alpha,\beta,\gamma,\delta$ with four diagonals of a cube, then $\cos^2\alpha+\cos^2\beta+\cos^2\gamma+\cos^2\delta$ is equal to:
→
$\int_{}^{} {\sqrt {1 - \sin 2x} \;} dx = ........,\;\;x \in (0,\;\pi /4)$
→