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$2 \mathrm{H}_{2}(\mathrm{g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$
the observed rate expression is, rate $=\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right] .$ The rate expression of the reverse reaction is
Reason : Rate of reaction remains constant during the course of reaction.
$\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}$
$\text { rate }=\mathrm{k}[\mathrm{A}]^{1 / 2}[\mathrm{~B}]^{1 / 2}$
The reaction is initiated by taking $1 \mathrm{M}$ concentration $A$ and $B$ each. If the rate constant $(k)$ is $4.6 \times 10^{-2} \mathrm{~s}^{-1}$, then the time taken for $\mathrm{A}$ to become $0.1 \mathrm{M}$ is . . . . . . . . . . sec. (nearest integer)
Find out the products of reaction
$\begin{array}{*{20}{c}}
{C{H_3} - CHC{H_2}CHO} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,}
\end{array}$
Product $(A)$ of the reaction is