MCQ
Which of the following is more basic than aniline?
- ✓Benzylamine
- BDiphenylamine
- CTriphenylamine
- D$p-$ Nitroaniline
✓
Answer
Correct option: A.
Benzylamine
a
Benzyl amine, $C_{6} H_{5} C H_{2}-\ddot{N} H_{2}$ is more basic than aniline because benzyl group $\left(C_{6} H_{5} C H_{2}-\right)$ is electron donating
Benzyl amine, $C_{6} H_{5} C H_{2}-\ddot{N} H_{2}$ is more basic than aniline because benzyl group $\left(C_{6} H_{5} C H_{2}-\right)$ is electron donating
group due to $+I$-effect. So, it is able to increase the electron density of $N$ of $-NH_{2}$ group. Thus, due to higher electron density, rate of donation of free pair of electron is increased, i.e. basic character is higher. Phenyl and nitro group are electron attractive groups, so they are able to decrease the electron density of $N$ of $\ddot{N} H_{2}$ group. Hence, they are less basic than aniline.
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