MCQ
Which of the following is not a peroxide
- A$Na_2O_2$
- B$CaO_2$
- ✓$PbO_2$
- D$H_2O_2$
✓
Answer
Correct option: C.
$PbO_2$
c
$PbO _2$ are not true peroxide because they do not liberate $H _2 O _2$ on treatment with dilute acids.
$PbO _2$ are not true peroxide because they do not liberate $H _2 O _2$ on treatment with dilute acids.
Lead $(IV)$ oxide and the lead atom shares its $4$ electrons $2$ each with oxygen atoms. In Peroxide there a bond sharing of two oxygen atoms as in:
Hydrogen Peroxide $H - O - O - H$
Water is an oxide $H - O - H$
Likewise $PbO _2$ is an oxide $P$ b has a valency $4$
$O = Pb = O$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Electrolyte can conduct electricity because
Ionic radii are
Major product of the reaction is
Reaction of $SO_3$ is easier in :
→Dipole moment is shown by
Select correct about the following change
→$NO_2^+ \to NO_2 \to NO_2^-$
The de-Broglie wavelength associated with a material particle is
In an equilibrium reaction for which $\Delta {G^o} = 0$, the equilibrium constant $K = $
→Consider the following sequence of $A$ can be
→$\underset{{{C}_{3}}{{H}_{6}}C{{l}_{2}}}{\mathop{A}}\,\,\xrightarrow[2.\,\,{{H}^{+}}\,\,(\min d)]{\begin{smallmatrix}
1\,.\,\,alcoholic\,\,KOH\,/\,\Delta \\
followed\,\,by\,\,NaN{{H}_{2}}\,/\,\Delta
\end{smallmatrix}}$ $B\,\xrightarrow[{{H}_{2}}{{O}_{2}}/\overset{\Theta }{\mathop{O}}\,H]{{{B}_{2}}{{H}_{6}}}C$
$A\,\xrightarrow{aq.\,\,KOH\,(excess)}C$
$CH_3CHO \xrightarrow{{LiAl{H_4}}} CH_3CH_2OH$
→Nucleophile added in this reaction