MCQ
Which of the following is not aromatic
- ABenzene
- BNaphthalene
- CPyridine
- ✓$1,3,5- $heptatriene
✓
Answer
Correct option: D.
$1,3,5- $heptatriene
d
(d) A compound is said to be aromatic if it is planar and there is complete delocalization of $\pi $ electrons, which is only possilble if it is a conjugated cyclic system and number of electrons used in delocalization is $(4n + 2)$. $1, 3, 5- $heptatriene is not an aromatic compound because complete delocalization of $\pi $ electrons, is not possible in it.
(d) A compound is said to be aromatic if it is planar and there is complete delocalization of $\pi $ electrons, which is only possilble if it is a conjugated cyclic system and number of electrons used in delocalization is $(4n + 2)$. $1, 3, 5- $heptatriene is not an aromatic compound because complete delocalization of $\pi $ electrons, is not possible in it.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The highest first ionisation energy among the following elements.
Which of the following is polar?
If $AB _{4}$ molecule is a polar molecule, a possible geometry of $AB _{4}$ is :
→According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as $(h = 6.62 \times 10^{-27} \ ergs,$$ \ c = 3 \times cm s^{-1}, $$\ N_A = 6.02 \times 10^{-23} \ mol^{-1})$
→The mole fraction of a solute in a $100$ molal aqueous solution .......... $\times 10^{-2}$
→(Round off to the Nearest Integer).
[Given : Atomic masses : $H : 1.0 \,u , O : 16.0\, u ]$
The solubility of $[Ag^+]$ and $[Cl^-]$ solution is $1.43\times 10^{-3}\,gL^{-1}$ then what is the value of $K_{sp}$ at $25\,^oC$ of $AgCl$ .
→$0.8\, \mathrm{~g}$ of an organic compound was analysed by Kjeldahl's method for the estimation of nitrogen. If the percentage of nitrogen in the compound was found to be $42\, \%$, then $....\,\mathrm{mL}$ of $1\, \mathrm{M}$ $\mathrm{H}_{2} \mathrm{SO}_{4}$ would have been neutralized by the ammonia evolved during the analysis.
→Nuclei tend to have more neutrons than protons at high mass numbers because
$A + 2B + 3C \rightleftharpoons A{B_2}{C_3}$ Reaction of $6.0\, g$ of $A$, $6.0\times10^{23}$ atoms of $B$, and $0.036\, mol$ of $C$ yields $4.8\, g$ of compound $AB_2C_3$ . If the atomic mass of $A$ and $C$ are $60$ and $80\, amu$, respectively, the atomic mass of $B$ is .............. $\mathrm{amu}$ (Avogadro no . $= 6 \times10^{23}$)
→The number of benzylic hydrogen atoms in ethylbenzene is :