MCQ
Which of the following is not isoelectronic
- A$N{a^ + }$
- B$M{g^{2 + }}$
- C${O^{2 - }}$
- ✓$C{l^ - }$
✓
Answer
Correct option: D.
$C{l^ - }$
d
(d) $N{a^ + }$$ = 1{s^2}\,2{s^2}\,2{p^6}$
(d) $N{a^ + }$$ = 1{s^2}\,2{s^2}\,2{p^6}$
$Mg++$ $ = 1{s^2}\,2{s^2}\,2{p^6}$
${O^{2 - }}$$ = 1{s^2}\,2{s^2}\,2{p^6}$
$C{l^ - }$$ = 1{s^2}\,2{s^2}\,2{p^6}3{s^2}3{p^6}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
${P_2}{O_5}$ is used extensively as a
→Total number of stereoisomers of the compound $1-$ bromo $-3-$ chloro cyclobutane
→The amount of copper metal deposited at cathode on passing electric current of $500$ mili ampere for $20\, minutes$ in cupric chloride solution is ............ $\mathrm{g}$
→The equilibrium constant for a reaction,
→$A + B \rightleftharpoons C + D$ is $1 \times 10^{-2}$ at $298\, K$ and is
$2$ at $273\, K$. The chemical process resulting in the formation of $C$ and $D$ is
Assertion : $Pb^{4+}$ compounds are stronger oxidizing agents than $Sn^{4+}$ compounds.
→Reason : The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to ‘inert pair effect’.
Product $(A)$ is
→The standard reduction potentials of $4$ elements are given below. Which of the following will be the most suitable reducing agent
→$I = -3.04\,V$,
$II = -1.90\,V$,
$III = 0\,V$,
$IV = 1.90\,V$
In Bohr’s model of atom when an electron jumps from $n =1$ to $n=3,$ how much energy will be absorbed
→The $IUPAC$ name of the compound shown below is :
→Chloro compound of vanadium has only spin magnetic moment of $1.73\, BM$. This vanadium chloride has the formula:
→