- A$NO^+$
- B$CO$
- C$O_2^-$
- ✓$CN^-$
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| Energy level | $K$ | $L$ | $M$ | $N$ |
| $n=1$ | $n=2$ | $n=3$ | $n=4.....n=\infty$ | |
| Energy | $- 864 \,a.u.$ | Zero |
the excitation energy needed to raise the electron from $M$ level to $n = \infty$ would be :
(Nearest integer)
$\left[\right.$ Given $\mathrm{K}_{m}=1 \times 10^{-14}$ and $\left.\mathrm{K}_{\mathrm{b}}=1.8 \times 10^{-5}\right]$
$\begin{array}{*{20}{l}}
{(u){H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHC{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (v){\mkern 1mu} C{H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHCl{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (w){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} H_2^ + {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (x){\mkern 1mu} H - C \equiv C - H} \\
{(y){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} N{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (z){\mkern 1mu} {{(C{H_3})}_2}C\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{N} N{H_2}}
\end{array}$
In an equilibrium mixture, the partial pressures are
$P_{S O_{3}}=43\,\mathrm{kPa} ; \quad P_{O_{2}}=530 \,\mathrm{~Pa}$ and
$\mathrm{P}_{\mathrm{SO}_{2}}=45\, \mathrm{kPa}$ The equilibrium constant $\mathrm{K}_{\mathrm{p}}=......\times 10^{-2} .$ (Nearest integer)
$N{H_4}^ + + {S^{ - 2}} \rightleftharpoons N{H_3} + H{S^ - }$